(y+3)^2=3(2y+6)

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Solution for (y+3)^2=3(2y+6) equation: 



(y+3)^2=3(2y+6)

We move all terms to the left:

(y+3)^2-(3(2y+6))=0



We calculate terms in parentheses: -(3(2y+6)), so:

3(2y+6)

We multiply parentheses

6y+18

Back to the equation:

-(6y+18)



We get rid of parentheses

(y+3)^2-6y-18=0

We add all the numbers together, and all the variables

-6y+(y+3)^2-18=0

We move all terms containing y to the left, all other terms to the right

-6y+(y+3)^2=18

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